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In the experiment below, under certain conditions, the concentration of P4 (g) was 0.4 M at 26 seconds and 0.7 M at 55 seconds. What is the rate of production of P4(g) in this experiment?

User AaronS
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The rate of production of P4(g) in this experiment is 0.01034 M/s, determined by the change in concentration over the time from 26 to 55 seconds.

The rate of production of P4(g) is calculated by determining the change in concentration over a specific time interval. In this case, the concentration increased from 0.4 M to 0.7 M, which is a change of 0.3 M, over a time period from 26 seconds to 55 seconds, which is 29 seconds. The rate of production would be the change in concentration divided by the time interval.

The calculation is as follows:

Rate of Production = (Final Concentration - Initial Concentration) / (Final Time - Initial Time)

Rate of Production = (0.7 M - 0.4 M) / (55 s - 26 s)

Rate of Production = 0.3 M / 29 s

Rate of Production = 0.01034 M/s

User Bluefoggy
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