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Extra Credit

Mercury has a mass of 3.2*10^23 kg. If an astronaut with a mass of 125 kg is standing on this
planet's surface and experiences a gravitational force of 902.83 Newtons what distance is the
astronaut from Mercury's center?

1 Answer

3 votes

Answer:4.72 * 10^6 meters

Explanation: the distance between the astronaut and Mercury's center, we can use the formula for gravitational force:

F = (G * m1 * m2) / r^2

Where:

- F is the gravitational force

- G is the gravitational constant (approximately 6.67430 x 10^-11 N m^2/kg^2)

- m1 and m2 are the masses of the two objects

- r is the distance between the centers of the two objects

In this case, we know the following information:

- Mass of Mercury (m1) = 3.2 * 10^23 kg

- Mass of the astronaut (m2) = 125 kg

- Gravitational force (F) = 902.83 N

We want to find the distance (r) between the astronaut and Mercury's center.

Rearranging the formula, we can solve for r:

r = sqrt((G * m1 * m2) / F)

Substituting the values into the formula, we get:

r = sqrt((6.67430 x 10^-11 N m^2/kg^2 * 3.2 * 10^23 kg * 125 kg) / 902.83 N)

Simplifying the calculation:

r ≈ 4.72 * 10^6 meters

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