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Unknown to the students of WHS, every time the school floors are waxed, Mr. Ramirez, the teacher, likes to slide down the hallway in his socks. Mr. Ramirez weighs 980 N and his coefficient of sliding friction between his socks and the floor is 0.123. What is the force of friction that opposes Mr. Ramirez’s motion down the hall?

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Final answer:

The force of friction opposing Mr. Ramirez's motion as he slides down the hallway is 120.54 N. This is calculated using the coefficient of sliding friction and his weight.

Step-by-step explanation:

The question is asking to calculate the force of friction that opposes Mr. Ramirez's motion as he slides down the hallway. Mr. Ramirez weighs 980 N and has a coefficient of sliding friction of 0.123.

The force of friction (f) can be calculated using the formula f = μN, where μ is the coefficient of kinetic friction and N is the normal force, which in this case is equal to the weight (w) since Mr. Ramirez is sliding on a horizontal surface.

N = w = 980 N.

By substituting the given values into the equation, we find the force of friction to be:

f = 0.123 × 980 N

= 120.54 N.

Therefore, the force of friction that opposes Mr. Ramirez’s motion down the hall is 120.54 N.