Question

Unknown to the students of WHS, every time the school floors are waxed, Mr. Ramirez, the teacher, likes to slide down the hallway in his socks. Mr. Ramirez weighs 980 N and his coefficient of sliding friction between his socks and the floor is 0.123. What is the force of friction that opposes Mr. Ramirez’s motion down the hall?

Answer 1

The force of friction opposing Mr. Ramirez's motion as he slides down the hallway is 120.54 N. This is calculated using the coefficient of sliding friction and his weight.

Step-by-step explanation:

The question is asking to calculate the force of friction that opposes Mr. Ramirez's motion as he slides down the hallway. Mr. Ramirez weighs 980 N and has a coefficient of sliding friction of 0.123.

The force of friction (f) can be calculated using the formula f = μN, where μ is the coefficient of kinetic friction and N is the normal force, which in this case is equal to the weight (w) since Mr. Ramirez is sliding on a horizontal surface.

N = w = 980 N.

By substituting the given values into the equation, we find the force of friction to be:

f = 0.123 × 980 N

= 120.54 N.

Therefore, the force of friction that opposes Mr. Ramirez’s motion down the hall is 120.54 N.