Question

Please solve the question given in the picture.​

Answer 1

`\sf\\i.\ \angle CDE=\angle CED\ \ \ [\textsf{Base angles of isosceles triangle are equal.}]\\\\ii.\ \angle CDE+\angle CED+\angle DCE=180^o\ \ \ [\textsf{Sum of angles of triangle is 180}^o.]\\or,\ \angle CDE+\angle CDE+40^o=180^o\\or,\ 2\angle CDE=140^o\\or,\ \angle CDE=70^o`

`\sf\\iii.\ \angle CDE=\angle BAD=70^o\ \ \ [\textsf{Corresponding angles are equal.}]\\or,\ y=70^o\\\\iv.\ \angle ABC+\angle BAD=180^o\ \ \ [\textsf{Co-interior angles are supplementary.}]\\or,\ x+y=180^o\\or,\ x+70^o=180^o\\or,\ x=110^o`