To solve the system of equations 2x + 3y = 6 and -5x + 2y = 4, use the method of elimination. The solution is x = 0 and y = 2.
To solve the system of equations:
2x + 3y = 6
-5x + 2y = 4
We can use the method of elimination.
Multiply the first equation by 5 and the second equation by 2 to make the coefficients of y the same:
10x + 15y = 30
-10x + 4y = 8
Add the two equations together:
19y = 38
Divide both sides by 19 to solve for y:
y = 2
Substitute the value of y back into either equation to solve for x.
Using the first equation:
2x + 3(2) = 6
2x + 6 = 6
2x = 0
x = 0
Therefore, the solution to the system of equations is x = 0 and y = 2.
Question:
Solve the system of equations below algebraically.
2x + 3y = 6
- 5x+2y=4