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Solve x²-5x+1=0 by using the quadratic formula.

A
B
C
D
X=
X=
X=
X =
-2-√29
5
-2-√21
5
5-2/29
2
5-√21
2
or x =
or x =
or x =
or x =
-2+√29
5
-2+√21
5
5+2√√/29
2
5+√21
2

Solve x²-5x+1=0 by using the quadratic formula. A B C D X= X= X= X = -2-√29 5 -2-√21 5 5-2/29 2 5-√21 2 or-example-1

1 Answer

6 votes

Final answer:

The quadratic equation x²-5x+1=0 is solved using the quadratic formula yielding two solutions: x = (5 - √21) / 2 and x = (5 + √21) / 2.

Step-by-step explanation:

To solve the quadratic equation x²-5x+1=0 using the quadratic formula, we first identify the coefficients a, b, and c in the equation ax² + bx + c = 0. Here, a = 1, b = -5, and c = 1. The quadratic formula is x = (-b ± √(b² - 4ac)) / (2a). Substituting the values into the formula gives:

x = (-(-5) ± √((-5)² - 4(1)(1))) / (2(1))
x = (5 ± √(25 - 4)) / 2
x = (5 ± √(21)) / 2

Thus, the solutions are:

  • x = (5 - √21) / 2
  • x = (5 + √21) / 2

The correct answers are x = (5 - √21) / 2 and x = (5 + √21) / 2.

User Mike Mellor
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