The unknown angles in the parallel lines are as follows:
m∠DCE = 35°
m∠CEF = 145°
How to find angles in a parallel lines?
When parallel lines are cut by a transversal line, angle relationships are formed such as same interior angles, corresponding angles, alternate angles etc.
Therefore, let's use the angle relationship to find the unknown angles as follows:
AB, CD and EF are parallel to each other.
Hence,
∠BAC = ∠ACD = 35 degrees(alternate angles)
CD bisect ∠ACE
Therefore,
∠ACD = ∠DCE = 35°
Let's find the m∠CEF
m∠CEF = 180 - 35 = 145° (same side interior angles are supplementary)