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Please help as fast as possible.

Please help as fast as possible.-example-1
User Greduan
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The unknown angles in the parallel lines are as follows:

m∠DCE = 35°

m∠CEF = 145°

How to find angles in a parallel lines?

When parallel lines are cut by a transversal line, angle relationships are formed such as same interior angles, corresponding angles, alternate angles etc.

Therefore, let's use the angle relationship to find the unknown angles as follows:

AB, CD and EF are parallel to each other.

Hence,

∠BAC = ∠ACD = 35 degrees(alternate angles)

CD bisect ∠ACE

Therefore,

∠ACD = ∠DCE = 35°

Let's find the m∠CEF

m∠CEF = 180 - 35 = 145° (same side interior angles are supplementary)

User Khalfani
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