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Write the slope-intercept form of the equation of a line with a slope of −58

that passes through the point (−14,6)
.

1 Answer

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Final answer:

To find the slope-intercept form of the line with a slope of -58 passing through (-14,6), we solve for the y-intercept b in the equation y = mx + b, resulting in the equation y = -58x - 812.

Step-by-step explanation:

The slope-intercept form of a linear equation is given by y = mx + b, where m represents the slope and b represents the y-intercept.

Given that the slope is -58 and the line passes through the point (-14,6), we can substitute these values into the slope-intercept form to find the equation.

Substituting the values, we get y = -58x + b. To find the value of b, we can substitute the coordinates of the point (-14,6): 6 = -58(-14) + b

Simplifying the equation gives us b = -58(-14) + 6. Solving this equation yields b = -812.

Therefore, the slope-intercept form of the equation is y = -58x - 812.

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