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a certain isotope has a half-life of 6.6 h and an atomic mass of 82.15 u. what will the activity in bq of a 1.18-g sample be after 17.4 h?

User Kiersten
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Final answer:

To calculate the activity of the isotope after a certain time, use the formula: Activity = Initial activity * (0.5)^(t / half-life). Substitute the given values to find the activity in bq of the sample after 17.4 h.

Step-by-step explanation:

To calculate the activity of the isotope after a certain time, we can use the formula: Activity = Initial activity × (0.5)^{(t / half-life)}

In this case, the initial activity is given as 1.18 g, and the half-life is 6.6 h. We need to convert the half-life to seconds to match the units of the activity, so 6.6 h is equal to 23760 s.

Substituting these values into the formula, we get: Activity = 1.18 g × (0.5)^{(17.4 h / 6.6 h)}

To calculate the activity of a 1.18-g sample of an isotope with a half-life of 6.6 hours after 17.4 hours, the decay formula A = A0(1/2)^(t/T) can be used, where A0 is the initial activity, t is the time, and T is the half-life.

User Iraj Jelodari
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