Final answer:
The height of the cliff is calculated by using the formula for the distance traveled under constant acceleration (d = 0.5 * g * t^2) with the given time of fall, which is found to be approximately 91.07 meters.
Step-by-step explanation:
The question asks to calculate the height of the cliff from which a stone is thrown horizontally with an initial speed and hits the ground after a certain time. To find the height of the cliff, we only consider the vertical motion since the horizontal speed does not affect the falling time.
With the acceleration due to gravity being 9.8 m/s2, and the time of fall being 4.3 s, we can use the formula for the distance traveled under constant acceleration, which is d = 0.5 * g * t2.
Plugging in the values we get: d = 0.5 * 9.8 m/s2 * (4.3 s)2. Carrying out the calculation gives the height of the cliff to be approximately 91.07 meters.