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calculate the absolute pressure at an ocean depth of 100 m. assume the density of sea water is 1 0²² kg/m³ and the air above exerts a pressure of 101.3 kpa.

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Final answer:

The absolute pressure at a depth of 100m in the ocean is calculated by adding the atmospheric pressure (101300 Pa) to the pressure exerted by the water column above, resulting in a total of 1,101,300 Pa or 1.1013 MPa.

Step-by-step explanation:

To calculate the absolute pressure at an ocean depth of 100 m, you need to consider both the pressure exerted by the atmosphere and the pressure exerted by the water above the point of interest.

The atmospheric pressure at sea level is given as 101.3 kPa, and you are provided with the density of seawater as 1.02×10³ kg/m³. Using the formula for pressure due to a fluid column, P = hρg, where h is the depth, ρ is the density, and g is the acceleration due to gravity, we can find the pressure due to the water column.

The acceleration due to gravity is approximately 9.81 m/s². Therefore, the pressure due to the seawater at 100 m can be calculated as:

Pwater = hρg = (100 m)(1.02×10³ kg/m³)(9.81 m/s²) = 1.00×10¶ Pa

To get the absolute pressure at this depth, you simply add the atmospheric pressure to the pressure due to the water:

Pabsolute = Patmosphere + Pwater = (101.3 kPa) + (1.00×10¶ Pa)

Before we can add these together, we need to convert the atmospheric pressure from kPa to Pa:

101.3 kPa = 101300 Pa

Now, adding them together:

Pabsolute = 101300 Pa + 1.00×10¶ Pa = 1,101,300 Pa

The absolute pressure at a depth of 100 m in the ocean is therefore 1,101,300 Pa or 1.1013 MPa.

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