Final answer:
To find the electric field needed to drive an 8.0 A current through a silver wire 0.95 mm in diameter, one must use Ohm's law along with the resistivity formula, assuming standard values of resistivity for silver and using geometrical calculations for the wire's cross-sectional area.
Step-by-step explanation:
To calculate the electric field necessary to drive an 8.0 A current through a silver wire with a diameter of 0.95 mm, we need to use Ohm's law (V=IR), where 'V' is the voltage across the wire, 'I' is the current through the wire, and 'R' is the resistance of the wire. First, we need to find the resistance using the resistivity formula (R= ρL/A), where 'ρ' represents the resistivity, 'L' is the length of the wire, and 'A' is the cross-sectional area of the wire.
Since the question does not provide the length of the wire or its resistivity, we'll need to look up the resistivity of silver (ρ) from a standard table. Taking Resistivity of silver as 1.59 × 10⁻⁸ Ω·m, and the cross-sectional area 'A' can be calculated using the formula for the area of a circle (A = πr²), given the diameter 'd' is 0.95 mm.
Assuming the wire is 1 meter in length for simplicity, the cross-sectional area 'A' would be (π(0.95/2)^2) × 10⁻⁶ m². The resistance 'R' can then be calculated. We can then apply Ohm's law (V=IR) to find the voltage 'V' needed to drive the 8.0 A current. Lastly, to find the electric field 'E', we use the electric field formula (E=V/L), where 'L' is again assumed to be 1 meter. This will give us the electric field in volts per meter (V/m).