Question

In a box there are 4 ball point pens, and 3 fountain pens. How many possible selections can be formed which have at least 2 items of every types of pen?

A. 26
B. 44
C. 52
D. 78
E. 130

Answer 1

To find the number of possible selections that have at least 2 items of every type of pen, we can use the concept of combinations. The number of choices for the ballpoint pens is 11 and for the fountain pens is 4. Multiplying these numbers gives the total number of possible selections as 44.

option B is the correct

Step-by-step explanation:

To find the number of possible selections that have at least 2 items of every type of pen, we can use the concept of combinations. Let's consider the two types of pens separately.

For the ballpoint pens, there are 4 pens and we need to choose at least 2. The number of ways to choose 2 or more ballpoint pens from 4 is given by: C(4, 2) + C(4, 3) + C(4, 4) = 6 + 4 + 1 = 11.

Similarly, for the fountain pens, there are 3 pens and we need to choose at least 2. The number of ways to choose 2 or more fountain pens from 3 is given by: C(3, 2) + C(3, 3) = 3 + 1 = 4.

To get the total number of possible selections, we multiply the number of choices for each type of pen: 11 * 4 = 44.

Therefore, the correct answer is B. 44.