Question

write a python program. Initially, string S of Length N is given. The nN-1 operations are appliedto it:move the first letter of S to the end. How many times is the first letternof S the same as the last letter. For example, given S= "abbaa" and the obtained sequence of strings is abbaa, bbaaa, baaab, aaabb, aabba. Three of them have the same first and last letter. Write a function def solution (S) thst given a string S of length N, consisting of letters ‘a’ and/or ‘b’, returns the number of times the efirst letter is the same as the last in the obtained sequence of the strings. Given S = "abbaa" the function should return 3. Given S = "aaa", the efunction should return 4. The first and last letters are always the same. Given S = "abab", the function should return 0. The first and last letters are always different. Write an efficient algorithms for the following assumptions

Answer 1

The Python function 'solution' counts the instances where the first and last letters of a string match after cyclically moving the first letter to the end of the string.

Step-by-step explanation:

The task requires writing a Python program to count how many times the first letter of a given string matches the last letter after repeatedly moving the first letter to the end. The following Python function accomplishes this:

def solution(S):
# Initialize a counter for the number of matches
count = 0
# Loop through each transformation of the string
for i in range(len(S)):
if S[0] == S[-1]:
count += 1
S = S[1:] + S[0] # Move the first letter to the end
return count

For example, calling solution('abbaa') would return 3 because 'abbaa', 'baaab', and 'aabba' have the same first and last letter.

To use the function, simply pass the string to the solution function like so:

result = solution('abbaa')
print(result) # Output will be 3

Answer 2

The Python function 'solution' calculates the number of times the first and last letters of the string S match after conducting N-1 operations, where each operation involves moving the first letter of S to the end.

Step-by-step explanation:

The task is to write a Python program that determines how many times the first letter of a string S is the same as the last letter after performing a series of operations. In each operation, the first letter of S is moved to the end. The function solution(S) will take the string S as an input and return the count of such operations where the first and last letters match.

Here's a step-by-step explanation and Python code for the solution function:

1. Define the function solution(S).
2. Initialize a counter variable to keep track of matching occurrences.
3. Iterate for a range from 0 to the length of S.
4. In each iteration, check if the first and last characters of S are identical.
5. If they match, increment the counter.
6. Move the first character to the end of the string S.
7. Return the counter after iterating through all operations.

Example Python Function:

def solution(S):
count = 0
for i in range(len(S)):
if S[0] == S[-1]:
count += 1
S = S[1:] + S[0]
return count

For S = "abbaa", the function would return 3. For S = "aaa", it returns 4, and for S = "abab", it returns 0.