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What is the concentration in %(m/v) of a solution prepared by mixing 3.0 g of a chemical (mw 180.156) in a total of 97.0 ml of solution?

a. 3.1% (m/v)
b. 0.17% (m/v)
c. 3.0% (m/v)
d. 60.1% (m/v)

1 Answer

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Final answer:

The concentration in % mass/volume of a solution prepared by mixing 3.0 g of a chemical 180.156 g/mol in a total of 97.0 mL of solution is approximately 3.1% m/v. The correct answer is option a.

Step-by-step explanation:

The question asks for the concentration of a solution in percentage mass/volume (%m/v), which is calculated by dividing the mass of the solute by the volume of the solution and then multiplying by 100. In the given scenario, a chemical with a molecular weight (mw) of 180.156 g/mol is dissolved to make a 97.0 mL solution, with the mass of the chemical being 3.0 g.

The formula to calculate %m/v is (mass of solute in grams / volume of solution in mL) × 100. To find the concentration of the solution, we use the information provided: (3.0 g / 97.0 mL) × 100 = 3.09%, which we can round to 3.1%. Therefore, the correct answer is a. 3.1% m/v. This value tells us that there are 3.1 grams of the chemical in every 100 mL of the solution.

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