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how did the solution appear after you mixed 1ml of 0.1 m copper (ii) sulfate with 5ml of 0.1 m sodium sulfide?

User Mannykary
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Final answer:

When copper (II) sulfate is mixed with sodium sulfide, a double displacement reaction occurs, and copper (II) sulfide is formed as a precipitate. The solution may appear cloudy or milky due to the solid particles of copper (II) sulfide. The presence of copper (II) ions gives the solution a light blue color.

Step-by-step explanation:

When you mix 1 ml of 0.1 M copper (II) sulfate with 5 ml of 0.1 M sodium sulfide, a chemical reaction called a double displacement reaction occurs. In this reaction, the copper (II) ions (Cu²⁺) from the copper (II) sulfate react with the sulfide ions (S²⁻) from the sodium sulfide to form a new compound called copper (II) sulfide (CuS).

This compound appears as a precipitate, which means it is insoluble and forms solid particles in the solution.

The chemical equation for this reaction is:

CuSO₄ + Na₂S → CuS + Na₂SO₄

The precipitate will appear as a solid in the solution, giving it a cloudy or milky appearance. In this case, since copper (II) sulfate is a blue compound, the resulting solution may have a light blue color due to the presence of copper (II) ions.

User Smit Gajera
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