Final answer:
By iterating over each digit, the program can identify odd numbers, add them to a sum, and multiply them to get the product, resetting the product to 0 if no odd digits are found.
Step-by-step explanation:
To write a program that takes a 4-digit number as input, we need to separate each digit and determine if it is odd. If the digit is odd, we will add it to a sum and multiply it into a product (initially set to 1 since multiplying by 0 would nullify the product). To ensure that the product remains 1 if no odd digits are found, we will only update the product when we encounter the first odd digit. Here is a simple example in Python:
number = int(input('Enter a 4-digit number: '))
sum_of_odds = 0
product_of_odds = 1
found_odd = False
for i in str(number):
digit = int(i)
if digit % 2 != 0: # Check if the digit is odd
sum_of_odds += digit
if not found_odd: # Update product only if an odd digit is found
found_odd = True
product_of_odds = digit
else:
product_of_odds *= digit
if not found_odd: # Reset product to 0 if no odd digits are found
product_of_odds = 0
print('Sum of odd digits:', sum_of_odds)
print('Product of odd digits:', product_of_odds)
The user is prompted to enter a 4-digit number, which is then processed to calculate the sum of the odd digits and the product of the odd digits. Note that in the case where there are no odd digits, the product remains 0 to indicate that no multiplication was performed.