Final answer:
The maximum shear stress on the element along the hydraulic lift cylinder on a truck is 2.5 MPa. A properly oriented element sketch would show the principal stresses along the x-axis and y-axis, and a diagonal arrow at a 45-degree angle representing the maximum shear stress
Step-by-step explanation:
To find the maximum shear stress on the element, we need to calculate the shear stress at a 45-degree angle to the principal stress. The maximum shear stress is given by the formula:
τ_max = |σ|/2
where τ_max is the maximum shear stress and σ is the principal stress. In this case, the principal stress is -5 MPa. Plug in the values:
τ_max = |-5 MPa|/2 = 2.5 MPa
Therefore, the maximum shear stress on the element is 2.5 MPa.
A sketch of a properly oriented element would show two arrows representing the principal stresses along the x-axis and y-axis, and a diagonal arrow at a 45-degree angle representing the maximum shear stress.