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If a number is selected at random from the first 200 natural numbers, what is the probability that it is divisible by both 6 and 8?

User Whittle
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Answer:

6 = 2 × 3, 8 = 2 × 2 × 2

LCM of 6 and 8 = 2 × 2 × 2 × 3 = 24

Of the first 200 natural numbers, 8 are divisible by both 6 and 8 (divisible by 24).

P(number divisible by 24) = 8/200 = 1/25

= 4%

User Azro
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