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When an electron jumps from the fourth orbit to the second orbit, one gets the

A. second line of paschen series

B. second line of balmer serie

C. first line pfund series

D. second line of lyman series

1 Answer

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Final answer:

When an electron transitions from the fourth orbit to the second orbit in a hydrogen atom, it emits a photon that corresponds to the second line of the Balmer series, visible in the spectrum.

"the correct option is approximately option B"

Step-by-step explanation:

When an electron jumps from the fourth orbit to the second orbit in a hydrogen atom, it emits a photon corresponding to the difference in energy between these two orbits. According to the Bohr model, this transition corresponds to the Balmer series, where electrons transition to the second energy level (n=2) from higher levels.

The Lyman series consists of transitions to the ground state (n=1), and results in ultraviolet radiation. The Paschen series, Brackett series, and Pfund series correspond to transitions to n=3, n=4, and n=5, respectively, and result in infrared radiation.

Since the electron in this question is transitioning to the n=2 state, the spectral line observed would be part of the Balmer series. The first line of the Balmer series corresponds to a transition from the third orbit to the second; consequently, a transition from the fourth orbit to the second would produce the second line of the Balmer series. Hence, the answer is B. second line of Balmer series.

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