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In a given distribution the coefficient of range is 29 and its maximum value is 64.5, find its minimum value

User Bei
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Final answer:

To find the minimum value of a distribution with a given coefficient of range and maximum value, you can use the coefficient of range formula. Through algebraic manipulation, the minimum value is calculated to be -60.1.

Step-by-step explanation:

To find the minimum value of a given distribution when the coefficient of range is 29 and the maximum value is 64.5, we can apply the formula for the coefficient of range. The coefficient of range is given by (Maximum value - Minimum value) / (Maximum value + Minimum value).

Let the minimum value be denoted as 'x'. We then have the equation:

29 = (64.5 - x) / (64.5 + x)

To solve for 'x', we can cross-multiply:

29(64.5 + x) = 64.5 - x

Then distribute 29 through the parentheses:

1867.5 + 29x = 64.5 - x

Now, we combine like terms:

29x + x = 64.5 - 1867.5

30x = -1803

Divide both sides by 30 to solve for x:

x = -1803 / 30

x = -60.1

Thus, the minimum value of the distribution is -60.1.

User Snowcrash
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