Question

A copper wire of length l metre is bent to form a circular loop. If I amp current flows through the loop, find out the magnitude of magnetic moment of the loop.

Answer 1

The magnetic moment of a circular loop formed from a copper wire with current I is calculated as μ = I * l2/(4π), where l is the length of the wire before it was bent into a circle.

Step-by-step explanation:

The question asks for the magnetic moment of a circular loop formed by bending a copper wire of length l meters, with a current I amperes flowing through it.

The magnetic moment (μ) is given by the product of the current (I) and the area of the loop (A). In the case of a circular loop, the area is calculated using the formula for the area of a circle, A = πr2, where r is the radius of the circle.

To find the radius of the loop, we use the circumference of the circle, which is equal to the original length of the wire: C = 2πr = l. From this, we can solve for the radius r = l/(2π). Substituting back into the area formula, A becomes (π(l/(2π))2), which simplifies to A = l2/(4π). Finally, the magnetic moment is μ = I * l2/(4π).