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The average translational kinetic energy of N2 gas molecules at ...........°C becomes equal to the K.E. of an electron accelerated from rest through a potential difference of 0.1 volt.

(Given kB = 1.38 × 10⁻²³ J/K)

User Opux
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The average translational kinetic energy of N2 gas molecules at approximately 86,485°C becomes equal to the kinetic energy of an electron accelerated from rest through a potential difference of 0.1 volt.

To determine the temperature at which the average translational kinetic energy of N2 gas molecules equals the kinetic energy of an electron accelerated through a potential difference of 0.1 volt, we can use the relationship between kinetic energy and temperature. The average translational kinetic energy (3/2k_bT) of gas molecules is related to temperature (T), where kB​ is the Boltzmann constant.

The kinetic energy of an electron accelerated through a potential difference (V) is given by eV, where e is the elementary charge. Setting these two expressions equal to each other, we get: 3/2kBT=eV

Now, rearranging the equation to solve for temperature (T), we get:

T= ​2eV/3kb

Given kB​=1.38×10^−23 J/K and V=0.1V, we can substitute these values to find T. The resulting temperature is approximately 86,485°C. Therefore, at this temperature, the average translational kinetic energy of N2 gas molecules matches the kinetic energy of an electron accelerated through a potential difference of 0.1 volt.

User Bakar
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