Question

When a particle of mass m is attached to a vertical spring of spring constant k and released, its motion is described by y(t)=y0sin²ωt, where ′y′ is measured from the lower end of unstretched spring. Then ω is :

Answer 1

The angular frequency ω in the equation y(t) = y0sin²ωt is equal to 2,who represents the motion of the particle.

Step-by-step explanation:

The equation y(t) = y0sin²ωt represents the motion of a particle attached to a vertical spring undergoing simple harmonic motion. In this equation, y(t) represents the displacement of the particle from its equilibrium position at time t, y0 is the amplitude of the motion, and ω is the angular frequency of the motion.

The angular frequency ω can be determined by comparing the given equation to the general equation for simple harmonic motion, which is given by y(t) = A sin(ωt + φ), where A is the amplitude and φ is the phase angle.

By comparing the given equation y(t) = y0sin²ωt with the general equation, we can see that the angular frequency ω is equal to 2.