Final answer:
The alkyl iodide that cannot be produced by the reaction of HI with an appropriate ether is (C₂H₅)₃CI due to the presence of a quaternary carbon atom, which is resistant to cleavage.
Step-by-step explanation:
The question asks which of the following alkyl iodides cannot be produced by the reaction of hydroiodic acid (HI) with an appropriate ether: (a) CH₃I, (b) C₂H₅I, (c) (CH₃)₃CI, or (d) (C₂H₅)₃CI. When ethers react with hydroiodic acid, the reaction generally results in the cleavage of the ether to form an alkyl iodide and an alcohol. However, this reaction typically works well with primary and secondary alkyl groups, whereas tertiary alkyl groups do not generally undergo such cleavage due to steric hindrance and the difficulty of forming a carbocation intermediate.
The correct answer to the student's question is (d) (C₂H₅)₃CI because it involves a quaternary carbon atom which does not easily undergo the cleavage reaction necessary to produce the corresponding alkyl iodide in this situation.