Question

write a c program to develop a menu driven program to perform arithmetic operations( ,-,/,*) and display the result using user defined functions.

Answer 1

To develop a menu-driven program in C to perform arithmetic operations and display the result using user-defined functions, follow these steps: create functions for each arithmetic operation, display a menu of options, call the corresponding arithmetic function based on the user's choice, and repeat until the user chooses to exit.

Step-by-step explanation:

To develop a menu-driven program in C to perform arithmetic operations and display the result using user-defined functions, you can follow these steps:

1. Create a function for each arithmetic operation: addition, subtraction, multiplication, and division.
2. In the main function, display a menu of options for the user to choose from.
3. Based on the user's choice, call the corresponding arithmetic function and pass the required input values.
4. Display the result obtained from the arithmetic function.
5. Repeat steps 2-4 until the user chooses to exit the program.

Here's a sample code snippet:

#include <stdio.h>

int addition(int a, int b) {
return a + b;
}

int subtraction(int a, int b) {
return a - b;
}

int multiplication(int a, int b) {
return a * b;
}

int division(int a, int b) {
return a / b;
}

int main() {
int choice, num1, num2, result;
while (1) {
printf("\\Menu:\\");
printf("1. Addition\\");
printf("2. Subtraction\\");
printf("3. Multiplication\\");
printf("4. Division\\");
printf("5. Exit\\");
printf("Enter your choice: ");
scanf("%d", &choice);
if (choice == 5)
break;
printf("Enter two numbers: ");
scanf("%d %d", &num1, &num2);
switch (choice) {
case 1:
result = addition(num1, num2);
break;
case 2:
result = subtraction(num1, num2);
break;
case 3:
result = multiplication(num1, num2);
break;
case 4:
result = division(num1, num2);
break;
default:
printf("Invalid choice!\\");
continue;
}
printf("Result: %d\\", result);
}
return 0;
}