Question

The locus Mdh was evaluated eletrophoretically and two alleles were found in the population (with the notation of 1 and 2). Calculate the genotypic and allelic frequencies. Assuming random mating, calculate the expected number of heterozygotes at the Mdh locus. Is this population in HWE at the Mdh locus? How could you tell? What is one probable reason why the population would be out of HW based on the result.

Genotypes (numbers)
Locus 1/1 1/2 2/2
Mdh 620 10 370

a. What is the allelic frequency for the allele 1 in this population?

Answer 1

The allelic frequency for allele 1 in the Mdh locus of the population is 0.625 or 62.5%, which is determined by the proportion of allele 1 occurrences among all alleles in the population's gene pool.

Step-by-step explanation:

The allelic frequency for allele 1 in this population can be calculated using the genotype numbers provided for the Mdh locus. In a population, the number of allele 1 can be found by counting its occurrence in the homozygotes 1/1, which contributes two alleles each, and in the heterozygotes 1/2, which contributes one allele.

The population consists of 620 individuals with genotype 1/1, 10 individuals with genotype 1/2, and 370 with genotype 2/2. Therefore, the total number of allele 1 in the population is (2 * 620) + (1 * 10) = 1250.

Since each individual has two alleles, the total number of alleles in the population is twice the number of individuals: (620 + 10 + 370) * 2 = 2000 alleles. The frequency of allele 1 is then calculated as the number of allele 1 divided by the total number of alleles, 1250 / 2000 = 0.625 or 62.5%.