Question

when tightening bolt, you push perpendiculrly on a wrench with a force of 150 n at a distance of 0.14 m from the center of the bolt. how much torque re you exerting relative to the center of the bolt?

Answer 1

The torque exerted relative to the center of the bolt is 21 N·m. When converting this torque to foot-pounds, it becomes 15.48 ft·lb.

Step-by-step explanation:

Torque is calculated by multiplying the force applied to an object by the distance from the center of rotation. In this case, the force applied is 150 N and the distance from the center of the bolt is 0.14 m. Therefore, the torque exerted relative to the center of the bolt can be calculated as:

Torque = force x distance = 150 N x 0.14 m = 21 N·m

To convert this torque to foot-pounds, we can use the conversion factor: 1 N·m = 0.7376 ft·lb. Therefore, the torque in foot-pounds can be calculated as:

Torque in ft·lb = 21 N·m x 0.7376 ft·lb / N·m = 15.48 ft·lb