Final answer:
Increasing the intensity of light while keeping the frequency constant and above the cutoff frequency increases the number of ejected electrons but does not change the maximum kinetic energy of the electrons, the cutoff frequency, or other properties like the work function and stopping voltage. option b is correct.
Step-by-step explanation:
The question pertains to the photoelectric effect and what happens when the intensity of light that is incident on a piece of metal is increased, specifically for light with a frequency greater than the cutoff frequency (fcutoff). Increasing the intensity of light has specific impacts on the photoelectric effect.
Firstly, it is important to clarify that increasing the intensity of light, assuming frequency (f) > cutoff frequency (fcutoff), will not affect the cutoff frequency (fcutoff), the work function of the metal, the frequency of the incident photons, the wavelength, or the stopping voltage. These factors remain constant because they are intrinsic properties of the metal and the light's frequency, which is not being changed.
- The number of electrons ejected will increase because there will be more photons to knock electrons out of the metal, assuming the frequency is above the threshold.
- The maximum kinetic energy (KEmax) of the ejected electrons is not affected by light intensity, as KEmax is determined by the energy of the individual photons, which depends on their frequency, not how many there are.