The height of the image produced by the diverging lens is approximately -5.85 cm.
To determine the height of the image formed by a diverging lens, we can use the lens formula:
1/f= 1/do+ 1/di, where f is the focal length of the lens, d0 is the object distance (distance from the lens to the object), and di is the image distance (distance from the lens to the image). For a diverging lens, the focal length is considered negative.
Given that the object distance (do) is 30 cm, the focal length (f) is -13 cm (since it's a diverging lens), and the object height is 2 cm, we can use the magnification formula:
M=− di/do
The resulting image height is approximately -5.85 cm, and the negative sign indicates that the image is inverted, which is typical for diverging lenses.