Question

suppose an 8085 uses a clock frequency of 3 mhz. the add instruction of an 8085 takes four t states to fetch and execute. how long is this (in microseconds to two decimal places, where 1 microsecond)

Answer 1

The ADD instruction on an 8085 microprocessor with a 3 MHz clock takes 1.33 microseconds to complete, which is calculated based on the number of T states and the clock period.

Step-by-step explanation:

The question pertains to the operation time of an ADD instruction on an 8085 microprocessor with a given clock frequency. To calculate the time taken for a single instruction, we can use the formula: Instruction time (T) = Number of T states * Clock period (TCP). Given a clock frequency (f) of 3 MHz, the clock period (TCP) is the reciprocal of the frequency, i.e., TCP = 1/f. Substituting the given frequency:

TCP = 1 / 3 MHz = 1 / 3,000,000 Hz = 0.333µs

Since the ADD instruction takes 4 T states, the time taken to complete the instruction is:

Instruction time (T) = 4 * 0.333µs = 1.332µs

Accordingly, the ADD instruction on an 8085 microprocessor with a clock frequency of 3 MHz takes approximately 1.33 microseconds.