Question

a new conveyor system at the local packaging plan will utilize a motor-powered mechanical arm to exert an average force of 990 n to push large crates for 8 meters in 6 seconds. (a) determine work done, (b) power output required of such a motor.

Answer 1

The work done by the motor is 7920 Joules, and the power output required of the motor for this task is 1320 Watts.

Step-by-step explanation:

The question you've asked involves finding the work done by a motor-powered mechanical arm and the power output required by the motor. To solve part (a), we use the formula for work done, which is the product of the force applied and the distance over which it is applied: Work = Force × Distance. Since we are given an average force of 990 N and a distance of 8 meters, the work done is simply 990 N × 8 m = 7920 Joules (J).

For part (b), the power output is the rate at which work is done, which can be found using the formula Power = Work / Time. We have calculated the work to be 7920 J and we are given a time of 6 seconds, so the power output is 7920 J / 6 s = 1320 Watts (W).