Question

a calorimeter has 45.5 grams of water with a temperature of 23 c a separte amount of the of water with a mass of 53.5 g was heated to 87 and pour into the calorimeter, the final temerpature of the mixture if 57 c, find the heat capacity of the calorimeter?

Answer 1

To find the heat capacity of the calorimeter, we can use the principle of conservation of energy. The heat gained by the water and the heat lost by the metal should be equal.

Step-by-step explanation:

To find the heat capacity of the calorimeter, we can use the principle of conservation of energy. The heat gained by the water and the heat lost by the metal should be equal.

We can use the formula:

Heat gained by water = Heat lost by metal

Mass of water × specific heat capacity of water × change in temperature of water = Mass of metal × specific heat capacity of metal × change in temperature of metal

Plugging in the given values:

• Mass of water = 45.5 g
• Specific heat capacity of water = 4.18 J/(g·°C)
• Change in temperature of water = Final temperature - Initial temperature = 57°C - 23°C = 34°C
• Mass of metal = 53.5 g
• Change in temperature of metal = Final temperature - Initial temperature = 57°C - 87°C = -30°C

Using these values, we can solve for the specific heat capacity of the metal.