Question

household hydrogen peroxide, H₂O₂, is commonly used as a cleaning agent. the concentration of H₂O₂ right out of the bottle is approximately 0.882 m. how much water, in ml, would you need to add to 35.8 ml of the original solution to make a 0.109 m solution?

Answer 1

To dilute 35.8 ml of a 0.882 M hydrogen peroxide solution to a 0.109 M solution, approximately 254.1 ml of water needs to be added.

Step-by-step explanation:

The question asks how much water is needed to dilute 35.8 ml of a 0.882 M hydrogen peroxide (H₂O₂) solution to make a 0.109 M solution. To find the answer, we can use the dilution formula M1V1 = M2V2, where M1 and V1 represent the molarity and volume of the concentrated solution, and M2 and V2 represent the molarity and volume of the diluted solution.

Using the values provided, 0.882 M for M1, 35.8 ml for V1, and 0.109 M for M2, we can calculate V2, which is the final volume of the diluted solution. Substituting the values into the equation gives us (0.882 M)(35.8 ml) = (0.109 M)(V2). Solving for V2 gives us V2 = (0.882 M)(35.8 ml) / (0.109 M), which results in approximately 289.9 ml as the final volume of the diluted solution.

To get the amount of water needed to be added, we subtract the original volume (V1) from the final volume (V2). So, the required amount of water is 289.9 ml - 35.8 ml, which equals 254.1 ml. Therefore, to prepare a 0.109 M solution from the original solution, we need to add approximately 254.1 ml of water to 35.8 ml of 0.882 M hydrogen peroxide.