Final answer:
The student asked for the magnetic deflection force on a proton in a uniform magnetic field. The calculation involves finding the proton's velocity using its given kinetic energy and then applying the Lorentz force equation, considering the magnetic field and the proton's charge.
Step-by-step explanation:
The question asks to determine the magnetic deflection force that acts on a proton with kinetic energy of 5.3 MeV entering a laboratory chamber with a uniform magnetic field of 0.012 T directed vertically upward. To calculate this force, we need to find the velocity of the proton using its kinetic energy, and then apply the Lorentz force equation, F = q(v x B), where F is the force, q is the charge of the proton, v is the velocity of the proton, and B is the magnetic field. Since the proton is moving horizontally from south to north, and the magnetic field is vertical, the angle between the velocity and the magnetic field is 90 degrees, and the force will be perpendicular to both the velocity and the field.
The kinetic energy (KE) of the proton is given by KE = (1/2)mv2, where m is the mass of the proton and v is its velocity. Solving for v, we find v = sqrt(2KE/m). With the charge of a proton given by q = 1.6 x 10-19 C, we can substitute the values into the Lorentz force equation to find the magnitude of the force.