Question

From the following data of ΔH, of the following reactions:

C(s)+1/2 O₂(g)⟶CO(g);ΔH=−110KJ
C(s)+H₂O(g)⟶CO(g)+H₂(g);ΔH=132KJ

The mole composition of the mixture of steam and oxygen on being passed over coke at 1273 K, keeping the temperature constant is:

a. 0.8/1
b. 0.6/1
c. 0.4/1
d. 0.2/1

Answer 1

The correct answer is option a. 0.8/1.

Step-by-step explanation:

To determine the mole composition of the mixture of steam and oxygen on being passed over coke at 1273 K, we can use the given data of ΔH and the balanced equations of the reactions:

1. C(s) + 1/2 O₂(g) ⟶ CO(g); ΔH = -110 kJ

2. C(s) + H₂O(g) ⟶ CO(g) + H₂(g); ΔH = 132 kJ

First, let's calculate the moles of CO produced from the first reaction. Since there is no information about the moles of C and O₂, we can assume the mole ratio is 1:1 (as carbon dioxide is not formed). So, the moles of CO produced from the first reaction is equal to the moles of C(s) used in the second reaction, which is 110 kJ / 132 kJ = 0.833.

Next, let's consider the formation of carbon monoxide from the second reaction. Since 1 mole of carbon monoxide is formed from 1 mole of carbon, the moles of CO produced is equal to the moles of C(s) used, which is 0.833.

Therefore, the mole composition of the mixture of steam and oxygen is 0.833/1. Answer: option a. 0.8/1.