Question

A distance of 2 cm separates two parallel plates, and a potential difference of 100 v is applied between them. the plates have an area of 1 m? each and are charged with equal and opposite charges such that the electric field bet.ueen the plates is 2.5 x 10⁶ wm. assuming the plates infinitely calculate magnitude of the force between plates.

Answer 1

To find the magnitude of the force between two charged parallel plates, calculate the surface charge density using the electric field and vacuum permittivity. Then, find the charge on one plate and apply Coulomb's law.

Step-by-step explanation:

The question pertains to the electric field between two charged parallel plates and the resulting force on one plate due to the presence of the other.

The potential difference (V) between the plates is given as 100 V, the separation (d) between the plates is 2 cm, and the electric field (E) is specified as 2.5 x 10⁶ V/m.

To calculate the force (F) between the plates, first, the surface charge density (σ) can be found using the relationship σ = ε₀ * E, where ε₀ is the vacuum permittivity (8.85 x 10⁻¹² C²/N·m²). Then, the charge (Q) on one plate is obtained by multiplying σ with the area (A) of the plate. Finally, the force is calculated using Coulomb's law, considering F = Q * E.