Final answer:
The power output of a Francis Turbine is computed by calculating the hydraulic power using the effective head and flow rate and then adjusting for the turbine's overall efficiency. The effective head accounts for the kinetic energy changes at the draft tube's inlet and outlet.The correct option is option c .
Step-by-step explanation:
The question asks for the power output in kW of a Francis Turbine given the total head, inlet velocity, discharge, and efficiencies. To calculate the power output, we need to use the formulas for hydraulic power with respect to the head and flow rate, and then apply the efficiency factors. The hydraulic power (P) provided by the head of water can be calculated as P=ρ g Q H, where ρ is the density of water (1000 kg/m3), g is the acceleration due to gravity (9.81 m/s2), Q is the discharge (flow rate), and H is the effective head.
The effective head takes into account the differences in kinetic energy between the inlet and the outlet of the draft tube, calculated using Bernoulli's principle. As the velocities at the inlet and exit of the draft tube are given, we can use the formula H = Hstatic + (v12 - v22)/(2g) where v1 and v2 are the velocities at the inlet and exit of the draft tube, respectively.
To find the actual power output of the turbine, we apply the overall efficiency (ηoverall) to the hydraulic power. Thus, the power output Poutput = ηoverall • P. Plugging in the given values, we calculate the power output and find the answer that aligns with the options provided in the question.