Question

Ammonia gas can be prepared by the reaction

CaO+2NH₄Cl------>2NH₃+H₂O+CaCl₂
If 112 g CaO reacts with 224 g NH4Cl, how many moles of reactants and products are there when the reaction is complete?

Answer 1

When the reaction is complete, there are 2 moles of CaO, 4.18 moles of NH4Cl, 2 moles of NH3, 1 mole of H2O, and 1 mole of CaCl2.

Step-by-step explanation:

In the given chemical reaction, 1 mole of CaO reacts with 2 moles of NH4Cl to produce 2 moles of NH3, 1 mole of H2O, and 1 mole of CaCl2. To determine the number of moles of reactants and products when the reaction is complete, we need to calculate the number of moles of CaO and NH4Cl given the masses provided.

First, we convert the given masses to moles using the molar mass of each substance:

Mass of CaO = 112 g/mol

Mass of NH4Cl = 224 g/mol

Next, we use the stoichiometry of the reaction to calculate the number of moles of reactants and products:

Number of moles of CaO = Mass of CaO / Molar mass of CaO = 112 g / 56 g/mol = 2 moles

Number of moles of NH4Cl = Mass of NH4Cl / Molar mass of NH4Cl = 224 g / 53.49 g/mol = 4.18 moles

Number of moles of NH3 = 2 moles (based on the stoichiometry of the reaction)

Number of moles of H2O = 1 mole (based on the stoichiometry of the reaction)

Number of moles of CaCl2 = 1 mole (based on the stoichiometry of the reaction)