Question

What is the concentration (M) of 39.88 mL of an unknown NaOH solution if it required 46.08 mL of 0.6592 M HCl to neutralize?

a. 0.7617
b. 0.825
c. 0.912
d. 0.778
e. 0.812

Answer 1

The concentration of the unknown NaOH solution is (a) 0.7617 M.

Step-by-step explanation:

To find the concentration (M) of the unknown NaOH solution, we can use the equation:

volume of HCl solution (L) x molarity of HCl = volume of NaOH solution (L) x molarity of NaOH

First, convert the volumes to liters:

39.88 mL = 0.03988 L

46.08 mL = 0.04608 L

Next, plug in the values into the equation:

0.04608 L x 0.6592 M = 0.03988 L x concentration (M)

Solve for the concentration:

concentration (M) = (0.04608 L x 0.6592 M) / 0.03988 L

concentration (M) = 0.7617 M