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The metal vanadium crystallizes in a body-centered cubic lattice. If the density of vanadium is 6.11 g/cm³ , what is the unit cell volume?

a. 2.1.38 x 10⁷ pm³
b. 6.1.99 x 10⁵ pm³
C. 3.98 x 10⁵ pm³
d. 5.44 x 10⁵ pm³
e 2.77 x 10⁷ pm³

User Okke
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1 Answer

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Final answer:

The correct answer is option (a) 2.1.38 x 10⁷ pm³.

Step-by-step explanation:

The metal vanadium crystallizes in a body-centered cubic lattice.

The unit cell volume for a body-centered cubic structure can be calculated using the formula:

V = a³

Where V is the unit cell volume and a is the edge length of the unit cell.

Given that the density of vanadium is 6.11 g/cm³, we can convert it to g/pm³ by multiplying by 10^15 since there are 10^15 pm³ in 1 cm³. Thus, the density of vanadium is 6.11 x 10^15 g/pm³.

Let's assume the edge length of the unit cell is 'x' pm, then the unit cell volume would be x³ pm³.

Using the given density and the formula for unit cell volume, we can set up the following equation:

x³ pm³ * (6.11 x 10^15 g/pm³) = 6.11 x 10^15 pm³

Solving for x, we find:

x³ pm³ = 6.11 x 10^15 pm³ / (6.11 x 10^15 g/pm³)

x³ = 1 pm³ / g

x = 1^(1/3) pm / g^(1/3)

x = 1 pm / g^(1/3)

As we can see, the unit of 'x' is pm. Therefore, the unit cell volume is 1 pm³ / g^(1/3) pm = g^(-1/3).

Therefore, the correct answer is option (a) 2.1.38 x 10⁷ pm³.

User LoG
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