Final answer:
The initial concentration of HCl is 0.288 M.
Step-by-step explanation:
To find the initial concentration of HCl, first, we need to determine the number of moles of NaOH used in the titration:
moles of NaOH = concentration of NaOH * volume of NaOH used (in L)
moles of NaOH = 0.180 M * 0.0160 L = 0.00288 mol
Since the balanced equation is 1:1 between NaOH and HCl, the number of moles of HCl in 10.0 mL of the acid solution is also 0.00288 mol.
The initial concentration of HCl can be calculated as:
concentration of HCl = moles of HCl / volume of HCl (in L)
concentration of HCl = 0.00288 mol / 0.0100 L = 0.288 M