Final answer:
The average acceleration of a body with a position function displacement(t) = 4t - 2t^2 during the third second is -4 m/s^2, as the acceleration is constant and does not depend on the time interval.
Step-by-step explanation:
To find the average acceleration of a body that moves such that its distance as a function of time is given by displacement(t) = 4t - 2t^2, we would first need to determine the velocity of the body as a function of time by taking the derivative of the displacement with respect to time.
Velocity, v(t), is given by the first derivative of displacement, v(t) = d(4t - 2t^2)/dt = 4 - 4t. Then, to find the acceleration, we take the derivative of the velocity, a(t) = d(4 - 4t)/dt = -4 m/s2. This means the acceleration is constant, and the average acceleration over any duration is simply the constant value of the instantaneous acceleration.
Therefore, the average acceleration during the third second or any other second is -4 m/s2.