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What is the equation of a line that passes through the points (-12 , -2) and (0, -5) ?

User Papkass
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Final answer:

The equation of a line that passes through the points (-12, -2) and (0, -5) is y = -1/4x - 5.

Step-by-step explanation:

The equation of a line that passes through specific points can be found by determining the slope (rise over run) and using the y-intercept to write the equation in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

To find the slope of the line passing through (-12, -2) and (0, -5), use the formula m = (y2 - y1) / (x2 - x1). So, the slope m is equal to (-5 - (-2)) / (0 - (-12)) = -3 / 12 = -1/4.

Now, use one of the points to solve for the y-intercept b. Let's use the point (0, -5), which gives us -5 = (-1/4)(0) + b, so the y-intercept b is -5. The final equation of the line is therefore y = -1/4x - 5.

User Eben Roux
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