Final answer:
The molarity of a solution with 0.127 mol of sucrose in 700 mL of solution is 0.1814 M, which is calculated by dividing the moles of sucrose by the volume of solution in liters (0.700 L).
Step-by-step explanation:
The molarity of a solution is defined as the number of moles of solute per liter of solution. To calculate the molarity of the sucrose solution, we use the formula molarity = moles of solute / liters of solution.
In this case, we have 0.127 mol of sucrose dissolved in 700 mL of solution, and we need to convert the volume from milliliters to liters by dividing by 1000. Hence, the volume in liters is 0.700 L.
The calculation is then: molarity = 0.127 mol / 0.700 L = 0.1814 M. Therefore, the molarity of the sucrose solution is 0.1814 mol/L, which can also be written as 0.1814 M. The molarity of 0.127mol of sucrose in 700ml of solution is 0.1814 M.