Question

A particle P moves along the x-axis. The velocity of P is vms⁻¹ at time t seconds, where

v=−2t²+16t−24 for t > 0
(a) Find the times when P is at instantaneous res

Answer 1

The maximum acceleration a car can achieve with a coefficient of static friction of 0.80 is 7.848 m/s², using the formula a = μ_s × g, where g is the acceleration due to gravity.

Step-by-step explanation:

The student is inquiring about the maximum acceleration a car can achieve based on a given coefficient of static friction.

To calculate this, one would use the formula a = μ_s × g, where μ_s is the coefficient of static friction and g is acceleration due to gravity (9.81 m/s²).

For a coefficient of static friction of 0.80, the maximum acceleration would be 0.80 × 9.81 m/s², which equates to 7.848 m/s². This represents the limit beyond which the tires would begin to slip, assuming other factors such as the slope of the road and weight distribution on the tires are ideally managed.