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X is a point due west of a point P. Y is a point due south of P. If the distances PX and PY are 10 km and 15 km respectively, calculate the bearing of X from Y?

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The bearing of X from Y is approximately 126.87 degrees.

Calculation of the bearing of X from Y:

Step 1: Diagram and information gathering

We are given the following information:

P is a point.

X is a point due west of P, 10 km away.

Y is a point due south of P, 15 km away.

Step 2: Create a right triangle

Imagine a right triangle with the following sides:

XY (hypotenuse): calculated using the Pythagorean theorem

PX (adjacent to angle at X): 10 km

PY (opposite to angle at X): 15 km

Step 3: Calculate the hypotenuse (XY)

Using the Pythagorean theorem:

XY^2 = PX^2 + PY^2

XY^2 = 10^2 + 15^2

XY = √(100 + 225)

XY = √325

XY ≈ 18.03 km

Step 4: Calculate the angle at X (θ)

We need the angle between PX and XY, which we'll call θ.

We can use the inverse cosine function (cos^-1) to calculate this angle:

cos(θ) = PX / XY

cos(θ) = 10 / 18.03

θ = cos^-1(10 / 18.03)

θ ≈ 53.13°

Step 5: Convert the angle to bearing

Bearings are measured clockwise from the north direction.

Since X is west of Y, the bearing of X from Y is 180 degrees minus the angle calculated in step 4:

Bearing of X from Y = 180° - θ

Bearing of X from Y = 180° - 53.13°

Bearing of X from Y ≈ 126.87°

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