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A parabola has its vertex at (2,-3) and its y-intercept at (0,5). Write an equation of the parabola in the form y=a(x-h)²+k y

User Azzurrio
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Final answer:

The equation of the parabola with vertex at (2, -3) and y-intercept at (0, 5) is y=2(x-2)^2-3.

Step-by-step explanation:

The question asks to write the equation of a parabola given the vertex $(2, -3)$ and its y-intercept $(0,5)$.

To start, the vertex form of the equation of a parabola is $y = a(x-h)^2+k$, where $(h, k)$ is the vertex.

We know the vertex $(h, k) = (2, -3)$.

To find the value of $a$, we can substitute the y-intercept into the equation, which gives us $5=a(0-2)^2-3$.

Solving for $a$ yields $a=2$.

Therefore, the equation of the parabola is $y=2(x-2)^2-3$.

User Sajadre
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