Question

The width of a rectangle is 6y-25 feet and the length is 2.5y+7

feet. Find the perimeter of the rectangle.

Answer 1

The perimeter of a rectangle with a width of 6y-25 feet and length 2.5y+7 feet is calculated by the formula P = 2 × width + 2 × length, yielding 17y - 36 feet.

Step-by-step explanation:

The question asks for the perimeter of a rectangle with a width of 6y-25 feet and a length of 2.5y+7 feet. To find the perimeter of a rectangle, you add up all the sides of the rectangle. The perimeter (P) of a rectangle is calculated by the formula P = 2 × width + 2 × length.

To apply the given measurements to the formula:

• The width is 6y-25 feet.
• The length is 2.5y+7 feet.

Substituting the values, we get:

P = 2(6y-25) + 2(2.5y+7)

Further simplifying gives us:

P = 12y - 50 + 5y + 14

Combining like terms, we find:

P = 17y - 36

Therefore, the perimeter of the rectangle is 17y - 36 feet.