Question

А sample of neon initially has a volume of 4.00 l at 14 ∘c . what is the new temperature, in degrees celsius, when the volume of the sample is changed at constant pressure and amount of gas to 6.00 l ?

Answer 1

To find the new temperature when a neon gas sample's volume is changed from 4.00 L to 6.00 L at constant pressure, we use Charles's Law. The new temperature, converted from Kelvin to Celsius, is approximately 157.6 °C.

Step-by-step explanation:

The question is asking to find the new temperature for a neon gas sample when its volume is changed from 4.00 L to 6.00 L at constant pressure. We can use Charles's Law (V1/T1 = V2/T2) for this calculation since the pressure and the amount of gas remain constant. First, we convert the initial temperature from degrees Celsius to Kelvin by adding 273.15, which gives us T1 = 14 °C + 273.15 = 287.15 K. Next, we set up the equation using Charles's Law with the initial volume (V1 = 4.00 L), the initial temperature (T1 = 287.15 K), the final volume (V2 = 6.00 L), and we will solve it for the final temperature (T2).

V1/T1 = V2/T2
4.00 L / 287.15 K = 6.00 L / T2
T2 = (6.00 L × 287.15 K) / 4.00 L
T2 = 430.725 K
Since the temperature we need to find must be in degrees Celsius, we convert T2 back to °C: T2 = 430.725 K - 273.15 = 157.575 °C.

Therefore, the new temperature of the neon gas sample when the volume is increased to 6.00 L at constant pressure is approximately 157.6 °C.